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Sorry, the section about Thermal shok parameter' hapens to be a little bit long... Should the definitions of the Thermal shok parameter' and Thermal loading remain at the thermal shock article, or should we cut them out to separate article(s)? dima 15:29, 18 March 2007 (UTC)[reply]

Alien 3 and thermal shock

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I'm loving the example of thermal shock in relation to the film Alien 3 - I'm curious to discover my lectures response if I cite this example in my assignment. —Preceding unsigned comment added by 217.42.5.15 (talk) 18:58, 18 January 2008 (UTC)[reply]

Process rather than Outcome?

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I am not sure whether it is correct to say that thermal shock is the cracking failure due to temp changes. Isn't Thermal shock the process of subjecting materials to rapid temperature changes and whether or not they fail is then a property of the material? Rufus79 (talk) 00:15, 18 April 2008 (UTC)Rufus[reply]

high thermal expansion coefficients - not really...?!

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First paragraph: "objects are particularly vulnerable to this form of failure [...] and high thermal expansion coefficients." I do not think that ceramics/glasses have a high thermal expansion coefficient. It is is rather pretty small (compared to metals and polymers). See also http://en.wikipedia.org/wiki/Coefficient_of_thermal_expansion

Cheers! —Preceding unsigned comment added by 138.25.107.58 (talk) 08:20, 17 June 2010 (UTC)[reply]

I notice this has been changed to "and low thermal expansion co...". This makes the sentence nonsense, as the shock is not DUE TO the LOW expansion at all. 99.146.99.238 (talk) 20:07, 28 February 2012 (UTC)[reply]

Overheating??

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The disambiguation page for overheating links to this. Honestly I think overheating is a different phenomenon. For example, a if electronic resistor run beyond its ratings may overheat and cause damage by burning. This is different from physical damage from a temperature gradient. — Preceding unsigned comment added by 107.0.227.186 (talk) 22:06, 27 May 2012 (UTC)[reply]

ice explanation is wrong

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>>>"Ice cubes placed in a glass of warm water crack by thermal shock as the exterior surface increases in temperature much faster than the interior. As ice has a larger volume than the water that created it, the outer layer shrinks as it warms and begins to melt, while the interior remains largely unchanged. This rapid change in volume between different layers creates stresses in the ice that build until the force exceeds the strength of the ice, and a crack forms, sometimes with enough force to shoot ice shards out of the container."

This is wrong. Ice has a positive coefficient of thermal expansion, just like most other solids, so heating it causes the outside to expand, not contract. Yes, water (between 0 and 4 celsius) contracts as you heat it, and yes ice is less dense than water, but neither of these facts have any bearing whatsoever on thermal shock. You can observe cracking by rapidly heating ice from say, -40 celsius to -10 celsius, with no melting involved at all.

I've edited the section to remove this misconception. 94.11.200.209 (talk) 15:41, 12 August 2017 (UTC)[reply]

Restoring Previous Content

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I have restored content from previous editors which was removed without explanation by 93.44.85.201 in addition to some new content. As the page exists now it is rather disordered and I would prefer a community decision on the definitions to show first on the page. — Preceding unsigned comment added by Bob Clemintime (talkcontribs) 01:27, 17 July 2020 (UTC)[reply]

Purpose of defining a new temperature parameter?

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I do not see the purpose of defining a temperature parameter () unique to this wikipedia page. I find the parameter to make things more confusing, especially it will change depending on the material under consideration. As a result, I have reverted the definition to that written by previous editors, which is more consistent with the notation used in the sources for this article.Bob Clemintime (talk) 15:37, 1 August 2020 (UTC)[reply]

வெப்ப அதிர்ச்சி

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வெப்ப அதிர்ச்சி 42.111.162.51 (talk) 13:40, 1 February 2023 (UTC)[reply]